使用正则表达式捕获文本行中的值

Question

I have a text line and I need capture the value "Keyword" key.

In this sample the value is "ConquestImageDate".

With my code below I can capture the value as ConquestImageDate".

But it has a '"' on the end.

I know I can use a replace to get rid off it.

But, I´d like to do it in the regex.

let line =
  '(0008,0023) VERS="CQ"   VR="DA"   VM="1"    Keyword="ConquestImageDate"             Name="Conquest Image Date"';
const re = /Keyword=\"\s*(\S+)/;
m = re.exec(line);
console.log(m[1]);

Answer 1

You are not matching the closing " , and as exec might yield null you can check for m first before indexing into it.

 let line = '(0008,0023) VERS="CQ" VR="DA" VM="1" Keyword="ConquestImageDate" Name="Conquest Image Date"'; const re = /Keyword="\s*(\S+)"/; m = re.exec(line); if (m) { console.log(m[1]); }

If there can also be unwanted whitespace chars at the end, you could making the \S non greedy.

 let line = '(0008,0023) VERS="CQ" VR="DA" VM="1" Keyword="ConquestImageDate" Name="Conquest Image Date"'; const re = /Keyword="\s*(\S*?)\s*"/; m = re.exec(line); if (m) { console.log(m[1]); }

---

You are matching Keyword which is singular, but if in any case you want to match spaces or newlines as well between the double quotes

\bKeyword="\s*([^"]*?)"

Regex demo