[英]In a Excel file how to find the background color of a cell using openpyxl (Python)
`wb = openpyxl.load_workbook('file.xlsx',data_only=True)
fs_count_row = fs.max_row
fs_count_col = fs.max_column
for a in range(1,fs_count_row):
cell_color = fs.cell(column=1, row=a)
bgColor = cell_color.fill.bgColor.index
fgColor = cell_color.fill.fgColor.index`
Tried using the above code.尝试使用上面的代码。 However, it works fine for some cells and give wrong output for some other cells.
但是,它对某些单元格工作正常,而对其他一些单元格给出错误的 output。 Can I know the reason why?
我能知道原因吗?
Column number was fixed to 1 always, that's why code is not picking up the cells outside of the first column.列号始终固定为1 ,这就是代码没有拾取第一列之外的单元格的原因。 Loop both rows and columns .
循环行和列。 Updated code below.
更新了下面的代码。 I've added a print statement to provide the fgcolor and bgcolor of all the active cells along with the cell information.
我添加了一个打印语句来提供所有活动单元格的 fgcolor 和 bgcolor 以及单元格信息。 In addition, I've added a condition to ignore the blank cells where there is no foreground or background color.
此外,我添加了一个条件来忽略没有前景色或背景色的空白单元格。
Input:输入:
Cell A1 = Yellow
Cell A2 = Blank
Cell B1 = Black
Cell B2 = Red
Code:代码:
import openpyxl
wb = openpyxl.load_workbook('Excel.xlsx',data_only=True)
fs = wb.active
fs_count_row = fs.max_row
fs_count_col = fs.max_column
for row in range(1,fs_count_row+1):
for column in range(1,fs_count_col+1):
cell_color = fs.cell(column=column, row=row)
bgColor = cell_color.fill.bgColor.index
fgColor = cell_color.fill.fgColor.index
if (bgColor=='00000000') or (fgColor=='00000000'):
continue
else:
print("Background color of cell (",row,column, ") is", bgColor)
print("Foreground color of cell (",row,column, ") is", fgColor)
Output: Output:
Background color of cell ( 1 1 ) is 64
Foreground color of cell ( 1 1 ) is FFFFFF00
Background color of cell ( 1 2 ) is 64
Foreground color of cell ( 1 2 ) is 1
Background color of cell ( 2 2 ) is 64
Foreground color of cell ( 2 2 ) is FFFF0000
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