这个计算平方根的算法是如何工作的？

Question

I have found a piece of mathematical code to compute the square root of a real value. I obviously understand the code itself, but I must say that I badly understand the math logic of that algorithm. How does it work exactly?

inline
double _recurse(const double &_, const double &_x, const double &_y)
 
        { double _result;
 
          if(std::fabs(_y - _x) > 0.001)
            _result = _recurse(_, _y, 0.5 * (_y + _ / _y));
          else
            _result = _y;
 
          return _result;
        }

inline 
double sqrt(const double &_) 

       { return _recurse(_, 1.0, 0.5 * (1.0 + _)); }

Answer 1

Assume that you want to compute √a and have found an approxmation x . You want to improve that approximation by adding some correction δ to x . In other terms, you want to establish

x + δ = √a

or

(x + δ)² = x² + 2xδ + δ² = a

If you neglect the small term δ² , you can solve for δ and get

δ ~ (a - x²)/(2x)

and finally

x + δ ~ (a + x²)/(2x) = (a/x + x)/2.

This process can be iterated and converges very quickly to √a .

---

Eg for a=2 and the initial value x=1 , we get the approximations

1, 3/2, 17/12, 577/408, 665857/470832, ...

and the corresponding squares,

1, 2.25, 2.00694444..., 2.0000060073049..., 2.0000000000045...