[英]The null-coalescing operator and throw
I've just noticed that when using throw with the null-coalescing operator, you cannot just use the keyword "throw" on its own, an exception must be included with it.我刚刚注意到,在将 throw 与 null-coalescing 运算符一起使用时,您不能只使用关键字“throw”,它必须包含异常。 The following code demonstrates what I mean:
以下代码演示了我的意思:
try
{
return GetName();
}
catch (NameNotFoundException ex)
{
string name = GetOtherName();
// this is legal
return name ?? throw ex;
// whereas this is not
return name ?? throw;
}
Is there any reason for this?这有什么原因吗? Would it be because
throw;
会不会是因为
throw;
doesn't constitute an expression, or is there more to it?不构成表达式,还是还有更多?
According to https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/proposals/csharp-7.0/throw-expression根据https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/proposals/csharp-7.0/throw-expression
a throw expression consists of the throw keyword followed by a null_coalescing_expression where the null_coalescing_expression throw 表达式由 throw 关键字后跟 null_coalescing_expression 组成,其中 null_coalescing_expression
must denote a value of the class type System.Exception, of a class type that derives from System.Exception or of a type parameter type that has System.Exception (or a subclass thereof) as its effective base class.
必须表示 class 类型 System.Exception 的值、从 System.Exception 派生的 class 类型或具有 System.Exception(或其子类)作为其有效基 ZA2F2ED4F8EBC2CBB4C21A29DC40 的类型参数类型的值。 If evaluation of the expression produces null, a System.NullReferenceException is thrown instead
如果表达式的评估产生 null,则会引发 System.NullReferenceException
return name?? throw;
does not satisfy this condition as only the throw expression would be allowed here, not a throw statement.不满足此条件,因为此处仅允许 throw 表达式,而不是 throw 语句。
At least that's how I read this.至少我是这么读的。
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