在 Haskell 中的两个列表上使用变量二进制操作

Question

I'm trying to write a program that takes in two lists and a binary operation and takes each element of one list and applies it to the other using the binary operation. I have it working but not sure how to change it so it works with any binary operator. Here's examples:

myFunction (+) [100,200,300] [4,3,2,1] would return
[96,97,98,99,196,197,198,199,296,297,298,299]

myFunction (+) [100,200,300] [4,3,2,1] would return
[96,97,98,99,196,197,198,199,296,297,298,299]

This is what I have working with specific binary operations

Answer 1

The simplest way is a list comprehension:

myFunction f xs ys = [f x y | x <- xs, y <- ys]

It may not even be worth defining a new function; instead, just inline that content to the call site.

This function is also available from the standard library by the names liftM2 and liftA2 .