在 React Router v6 中检测重定向的 url

Question

I am using React v6, and I want to have a button that redirects the user to the page which redirected him to the current page.

And I know this question may hold two different questions, so here's what's exactly the question is focusing on:

• the page which redirected to the current page is not from another domain.
• the user got redirected to the current page by clicking a button somewhere else in the same react app I'm working on.

I couldn't find a clean way to do so using react v6, all the other answers are showing solutions using obsolete and extremely old versions of react-router-dom .

Answer 1

Isn't it an option just to use something like that?

    const navigate = useNavigate();
    ...
    navigate(-1);

Answer 2

i am not sure if you want to do something in the page from where you are redirecting. if you want to redirect instantly you can do the following

const navigate = useNavigate()
...
// when clicked on button
const handleClick = () => {
  navigate("redirect")
  navigate("current url", { replace: true })
}