[英]how to make column values based on the values in two different column in R?
https://docs.google.com/spreadsheets/d/1dSmvEVlQvEmOfM4XmnnWkBA9u63jd0cw/edit?usp=sharing&ouid=106886848816525796522&rtpof=true&sd=true https://docs.google.com/spreadsheets/d/1dSmvEVlQvEmOfM4XmnnWkBA9u63jd0cw/edit?usp=sharing&ouid=106886848816525796522&rtpof=true&sd=true
I have date wise data of property and their future net rental month wise, i want to make one more column in which if any property having three days or less than three days of net rental 0 in every month, i want to state it as sandwitch date otherwise state it as null(as shown above) in R.我有财产的日期数据及其未来的净租金月份,我想再写一列,如果任何财产每个月的净租金为 0 天或少于 3 天,我想把它当作三明治否则日期 state 在 R 中为 null(如上所示)。
structure(list(Property_sku = c("1B-Mag-540", "1B-Mag-540", "1B-Mag-540",
"1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540",
"1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540",
"1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540", "1B-Mag-540",
"2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048",
"2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048",
"2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048",
"2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048", "2B-Tajer-6048"
), Date = structure(c(1660176000, 1660262400, 1660348800, 1660435200,
1660521600, 1660608000, 1660694400, 1660780800, 1660867200, 1660953600,
1661990400, 1662076800, 1662163200, 1662249600, 1662336000, 1662422400,
1662508800, 1662595200, 1660176000, 1660262400, 1660348800, 1660435200,
1660521600, 1660608000, 1660694400, 1660780800, 1662336000, 1662422400,
1662508800, 1662595200, 1662681600, 1662768000, 1662854400, 1662940800
), class = c("POSIXct", "POSIXt"), tzone = "UTC"), Month = c("August",
"August", "August", "August", "August", "August", "August", "August",
"August", "August", "September", "September", "September", "September",
"September", "September", "September", "September", "August",
"August", "August", "August", "August", "August", "August", "August",
"September", "September", "September", "September", "September",
"September", "September", "September"), Year = c("2022", "2022",
"2022", "2022", "2022", "2022", "2022", "2022", "2022", "2022",
"2022", "2022", "2022", "2022", "2022", "2022", "2022", "2022",
"2022", "2022", "2022", "2022", "2022", "2022", "2022", "2022",
"2022", "2022", "2022", "2022", "2022", "2022", "2022", "2022"
), Property_type = c("1B", "1B", "1B", "1B", "1B", "1B", "1B",
"1B", "1B", "1B", "1B", "1B", "1B", "1B", "1B", "1B", "1B", "1B",
"2B", "2B", "2B", "2B", "2B", "2B", "2B", "2B", "2B", "2B", "2B",
"2B", "2B", "2B", "2B", "2B"), Area = c("Downtown", "Downtown",
"Downtown", "Downtown", "Downtown", "Downtown", "Downtown", "Downtown",
"Downtown", "Downtown", "Downtown", "Downtown", "Downtown", "Downtown",
"Downtown", "Downtown", "Downtown", "Downtown", "Downtown", "Downtown",
"Downtown", "Downtown", "Downtown", "Downtown", "Downtown", "Downtown",
"Downtown", "Downtown", "Downtown", "Downtown", "Downtown", "Downtown",
"Downtown", "Downtown"), `Net Rental` = c(322, 264, 0, 0, 0,
557, 647, 252, 344, 121, 242, 0, 0, 555, 555, 555, 555, 555,
221, 0, 896, 896, 896, 896, 44, 342, 0, 0, 0, 0, 0, 0, 0, 0)), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -34L))
library(dplyr)
df = df %>%
group_by(Property_sku, Month, Year) %>%
mutate(
type = ifelse(`Net Rental` == 0 & sum(`Net Rental` == 0) <= 3, "sandwitch date", "")
) %>%
ungroup()
df
# # A tibble: 34 × 8
# Property_sku Date Month Year Property_type Area `Net Rental` type
# <chr> <dttm> <chr> <chr> <chr> <chr> <dbl> <chr>
# 1 1B-Mag-540 2022-08-11 00:00:00 August 2022 1B Downtown 322 ""
# 2 1B-Mag-540 2022-08-12 00:00:00 August 2022 1B Downtown 264 ""
# 3 1B-Mag-540 2022-08-13 00:00:00 August 2022 1B Downtown 0 "sandwitch date"
# 4 1B-Mag-540 2022-08-14 00:00:00 August 2022 1B Downtown 0 "sandwitch date"
# 5 1B-Mag-540 2022-08-15 00:00:00 August 2022 1B Downtown 0 "sandwitch date"
# 6 1B-Mag-540 2022-08-16 00:00:00 August 2022 1B Downtown 557 ""
# 7 1B-Mag-540 2022-08-17 00:00:00 August 2022 1B Downtown 647 ""
# 8 1B-Mag-540 2022-08-18 00:00:00 August 2022 1B Downtown 252 ""
# 9 1B-Mag-540 2022-08-19 00:00:00 August 2022 1B Downtown 344 ""
# 10 1B-Mag-540 2022-08-20 00:00:00 August 2022 1B Downtown 121 ""
# 11 1B-Mag-540 2022-09-01 00:00:00 September 2022 1B Downtown 242 ""
# 12 1B-Mag-540 2022-09-02 00:00:00 September 2022 1B Downtown 0 "sandwitch date"
# 13 1B-Mag-540 2022-09-03 00:00:00 September 2022 1B Downtown 0 "sandwitch date"
# 14 1B-Mag-540 2022-09-04 00:00:00 September 2022 1B Downtown 555 ""
# 15 1B-Mag-540 2022-09-05 00:00:00 September 2022 1B Downtown 555 ""
# 16 1B-Mag-540 2022-09-06 00:00:00 September 2022 1B Downtown 555 ""
# 17 1B-Mag-540 2022-09-07 00:00:00 September 2022 1B Downtown 555 ""
# 18 1B-Mag-540 2022-09-08 00:00:00 September 2022 1B Downtown 555 ""
# 19 2B-Tajer-6048 2022-08-11 00:00:00 August 2022 2B Downtown 221 ""
# 20 2B-Tajer-6048 2022-08-12 00:00:00 August 2022 2B Downtown 0 "sandwitch date"
# 21 2B-Tajer-6048 2022-08-13 00:00:00 August 2022 2B Downtown 896 ""
# 22 2B-Tajer-6048 2022-08-14 00:00:00 August 2022 2B Downtown 896 ""
# 23 2B-Tajer-6048 2022-08-15 00:00:00 August 2022 2B Downtown 896 ""
# 24 2B-Tajer-6048 2022-08-16 00:00:00 August 2022 2B Downtown 896 ""
# 25 2B-Tajer-6048 2022-08-17 00:00:00 August 2022 2B Downtown 44 ""
# 26 2B-Tajer-6048 2022-08-18 00:00:00 August 2022 2B Downtown 342 ""
# 27 2B-Tajer-6048 2022-09-05 00:00:00 September 2022 2B Downtown 0 ""
# 28 2B-Tajer-6048 2022-09-06 00:00:00 September 2022 2B Downtown 0 ""
# 29 2B-Tajer-6048 2022-09-07 00:00:00 September 2022 2B Downtown 0 ""
# 30 2B-Tajer-6048 2022-09-08 00:00:00 September 2022 2B Downtown 0 ""
# 31 2B-Tajer-6048 2022-09-09 00:00:00 September 2022 2B Downtown 0 ""
# 32 2B-Tajer-6048 2022-09-10 00:00:00 September 2022 2B Downtown 0 ""
# 33 2B-Tajer-6048 2022-09-11 00:00:00 September 2022 2B Downtown 0 ""
# 34 2B-Tajer-6048 2022-09-12 00:00:00 September 2022 2B Downtown 0 ""
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.