谷歌云 function 在测试期间崩溃，即使部署很好

Question

I built a cloud function (a very simple function - not very efficient). Below is the code and screenshot-

import functions_framework
import requests
@functions_framework.http
def hello():
    URL='https://api.openweathermap.org/data/2.5/weather?lat=36&lon=139&appid=a70f3b4f60b2f4c64e7aad63df5758d7'
    r = requests.get(url = URL)
    data = r.json()
    b={}
    b['temp']=data['main']['temp']
    b['pressure']=data['main']['pressure']
    return b
print(hello())

Delopyment code

I am trying to get the temperature and pressure for a location. The log is attached below and values are being fetched - log file

However, there is an error called "hello() takes 0 positional arguments but 1 was given" which I am unable to fix.

Could someone please help me?

Answer 1

Cloud Functions will be executed under events and in your case an HTTP event. The registered function (in this case hello ) will always receive an argument which is the HTTP request done to the function.

In fact this is very clear in the docs :

In Python, you register an HTTP handler function with the Functions Framework for Python.Your HTTP handler function must accept a Flask request object as an argument and return a value that Flask can convert into an HTTP response object.

The code could be:

import functions_framework
import requests

@functions_framework.http
def hello(request):
    URL='https://api.openweathermap.org/data/2.5/weather?lat=36&lon=139&appid=a70f3b4f60b2f4c64e7aad63df5758d7'
    r = requests.get(url = URL)
    data = r.json()
    b={}
    b['temp']=data['main']['temp']
    b['pressure']=data['main']['pressure']
    return b

I'd highly recommend to first read the docs since it seems you've not understood Cloud Functions completely. Basically Cloud Functions work as a very tiny web app.

As well I don't recommend to print the result. The point of using an HTTP Cloud Function is to get an HTTP response and not going to the logs every time to view that.

Finally the fact that the build is ok does not mean the function at runtime will work as expected.

Answer 2

Declare hello like this:

def hello(request):

This also means you cannot call the function like this:

print(hello())

The Python decorator @functions_framework.http defines the functions's signature.