如何 select 使用 MYSQL 来自不同表的多行

Question

I have 4 tables. From table1 , I would like to select postID , status , and data . From table2 , I would like to select postID , status , and update . Both table1 and table2 share 2 columns, which are the postID and the userID .
Table3 has a column postID which is common to table2 and table2.
I would like to query data from table1 and table2 based on the userID from the user table, then used the postID to query data from table3.

    $sql = "((SELECT `postID`, `status`, `data`
    FROM `table1`
    LEFT JOIN `users` 
    ON users.user_id=table1.userID 
    WHERE table1.userID=:userID 
    AND table1.active=:active)
    UNION 
    (SELECT `postID`, `status`, `update`
    FROM `table2`
    LEFT JOIN `users` 
    ON users.user_id=table2.userID 
    WHERE table2.userID=:userID 
    AND table2.active=:active
    ORDER BY table1.postID DESC))
    AS tab12
    LEFT JOIN `table3`
    ON table3.postID=:tab12.postID
    WHERE table3.active=:active";
    $stmt = $this->pdo->prepare($sql);
        $stmt->bindValue(":userID", $userID, PDO::PARAM_INT);
        $stmt->bindValue(":active", $active, PDO::PARAM_INT);
        $stmt->execute();

How to go to table3 and select only some columns: status, update, timeDate, then associate the results to the previous query?
Something like:

    $sql = "SELECT `status`, `update`, `timeDate` 
    FROM `table3` 
    WHERE postID=:tab12.postID
    AND active=:active";
    $stmt = $this->pdo->prepare($sql);
        $stmt->bindValue(":postID", $postID, PDO::PARAM_INT);
        $stmt->bindValue(":active", $active, PDO::PARAM_INT);
        $stmt->execute();

Answer 1

Select result.PostID, result.Status, result.data, T2.Status,                 
result.update, user.status, user.update, user.timeDate
from (Select T1.PostID, T1.Status, T1.data, T2.Status, T2.update
from table1 as t1
union table2 as T2
where T1.UserID = T2.UserID) result
union user 
where result.PostID = User.PostID