[英]in C++, can template function taking class object instantiate object with it's constructors arguments?
let's say i have a template function taking a class object:假设我有一个模板 function 采用 class object:
template<class T>
void Foo(T obj);
and a class definition as follows:和 class 定义如下:
class Bar
{
public:
Bar(int a, bool b): _a(a), _b(b) {}
private:
int _a;
bool _b;
};
is there a way to make the following code compile?有没有办法编译下面的代码?
Foo<Bar>(5,false);
Foo<Bar>({5,false}); // i know this works, just wondering if i can remove the brackets somehow.
Yes, this can be done with variadic templates and forwarding, and has many standard examples, like std::make_unique
.是的,这可以通过可变参数模板和转发来完成,并且有许多标准示例,例如std::make_unique
。
In your case it would be:在您的情况下,它将是:
template<class T, class ...Args>
void Foo(Args &&...args)
{
T obj { std::forward<Args>(args)... };
// use obj
}
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