如何使用 selenium、python 列出网站中的所有可点击链接？

Question

I am new to selenium. I want to navigate to www.cisco.com and list all the clickable buttons by their names (and respective xpaths too if possible) in a list like

['Log in','Products and services','Solutions',....etc. ]

I can navigate to the site using a chrome browser exe as given below:

from selenium import webdriver
from selenium.webdriver.common.by import By
chromedriver_location = "C:\\Path\\To\\chromedriver"

driver = webdriver.Chrome(chromedriver_location)
driver.get('https://cisco.com/')

first_popup_close='//*[@id="onetrust-close-btn-container"]/button'
supposedly_front_page='//*[@id="wcq"]'
#Close the pop-up
driver.find_element("xpath", first_popup_close).click()

#If I am not wrong in selecting the XPATH..
ids = driver.find_elements(By.XPATH, supposedly_front_page)

for i in ids:
    #print i.tag_name
    print(i.get_attribute("name"))    # Does not work as expected

I even tried using find_element(By.LINK_TEXT, "Log in") , find_element(By.PARTIAL_LINK_TEXT, "Log") etc. just to find only the 'Log in' button (in case my front page XPATH may be wrong), but it does not return the output (empty list).
The issue is - selenium doc has vague information about such or may be I am not able to find the required info. The older posts about the same does not work mostly as lots of functions have been deprecated by now.

Answer 1

If you like to get the login button for example from this page do:

loginbtn = driver.find_element_by_xpath("//button[@id='fwt-profile-button']")

or if you'd like to get all buttons you can identify them by doing:

btns = driver.find_elements_by_xpath("//button")