[英]How to stock a list in a Django Model?
I'm trying to stock a list in a Django Model like this:我正在尝试在 Django Model 中存储一个列表,如下所示:
class Search(models.Model):
result = models.CharField(max_length=100,
null=True, blank=True)
name = models.BooleanField(default=True)
eotp = models.BooleanField(default=True)
reference = models.BooleanField(default=True)
date = models.BooleanField(default=True)
contains = []
But I don't think that it's the best way to stock a list, because I have an error when i want to create an element (like this):但我不认为这是存储列表的最佳方式,因为当我想创建一个元素时出现错误(像这样):
new_search = Search(result=result, name=name, eotp=eotp, reference=reference, date=date, contains=contains)
"Search() got an unexpected keyword argument 'contains'" “Search() 得到了一个意外的关键字参数‘包含’”
Do you know if there is a better way to stock lists in django models or if I have to do this in another way?你知道在 django 型号中是否有更好的方法来库存清单,或者我是否必须以其他方式这样做?
Thanks谢谢
You need to use django's ArrayField
so that you can stock your list into your model.您需要使用 django 的
ArrayField
,以便您可以将列表存入 model。
Use this code for your model:将此代码用于您的 model:
class Search(models.Model):
result = models.CharField(max_length=100,
null=True, blank=True)
name = models.BooleanField(default=True)
eotp = models.BooleanField(default=True)
reference = models.BooleanField(default=True)
date = models.BooleanField(default=True)
contains = ArrayField(models.CharField(max_length=200), blank=True) #---> Set as per your requirements
Documentation: https://docs.djangoproject.com/en/4.1/ref/contrib/postgres/fields/#arrayfield文档: https://docs.djangoproject.com/en/4.1/ref/contrib/postgres/fields/#arrayfield
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