如何解决这个问题：ValueError：int() 的无效文字，基数为 10：

Question

student_heights = input("Input a list of student heights ").split()

for n in range(0, len(student_heights)): 
  student_heights[n] = int(student_heights[n])

total_height =0
for i in student_heights:
    total_height += i
print(total_height)

Answer 1

for n in range(0, len(student_heights)):
    if student_heights[n].isalpha():
        print("Enter only num's list, not letters")

        exit(1)

    student_heights[n] = int(student_heights[n])

Add if student_heights[n].isalpha() if is any letter in list of students height.
( isalpha() is checking if are in your list/text are letters, if it is, it return True , if not False )
exit() , if True it will exit.

Answer 2

the default behaviour of split() is to split by whitespace. You code would not throw errors if the input only contained numbers and whitespaces, eg 156 178 165 171 187 .

If you want a different split seperator, eg the comma , , you could use split(",") instead.

Valid input would be eg 156,178,165,171,187 .

Note that [156,178,165,171,187] is not valid input. It would split the string only at the comma, resulting in the first element to be equal to [156 , clearly not a valid number.

If you want to skip the input step and use a list instead, replace:

student_heights = input("Input a list of student heights ").split()

with:

student_heights = [156,178,165,171,187]

If you realy need to pass [156,178,165,171,187] as an input, you could also use literal_eval to convert it to a list. Don't forget to import the required module:

from ast import literal_eval
student_heights = literal_eval(input("Input a list of student heights "))

for n in range(0, len(student_heights)): 
  student_heights[n] = int(student_heights[n])

total_height =0
for i in student_heights:
    total_height += i
print(total_height)