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React组件中for循环内的setTimeout永远不会停止迭代

[英]setTimeout inside for loop in React component never stops iterating

I am trying to create a simple counter component in React.我正在尝试在 React 中创建一个简单的计数器组件。 It should start at 0, then iterate up to the passed in number.它应该从 0 开始,然后迭代到传入的数字。 Here is the code I currently have:这是我目前拥有的代码:

const Counter = ({ number }) => {
  const [currentNumber, setCurrentNumber] = useState(0);

  for (let i = 0; i < number; i++) {
    setTimeout(() => setCurrentNumber(currentNumber + 1), 2000);
  }

  return <span>{currentNumber}</span>;
};

export default Counter;

What happens when I run this, is it basically keeps counting forever.当我运行它时会发生什么,它基本上一直在计数。 currentNumber never stops incremementing, even once the number has been reached. currentNumber永远不会停止递增,即使达到该number也是如此。

You should add currentNumber as a dependency for useEffect() .您应该添加currentNumber作为useEffect()的依赖项。 This way useEffect() will get triggered every second and a new timeout will be registered but only as long as currentNumber is smaller than number .这样useEffect()将每秒触发一次,并且将注册一个新的超时,但前提是currentNumber小于number

 const Counter = ({ number }) => { const [currentNumber, setCurrentNumber] = React.useState(0); React.useEffect(() => { if(currentNumber < number) setTimeout(() => setCurrentNumber(currentNumber + 1), 1000); }, [currentNumber]); return <span>{currentNumber}</span>; }; ReactDOM.render(<Counter number={20}/>, document.getElementById('root'));
 <script crossorigin src="https://unpkg.com/react@18/umd/react.production.min.js"></script> <script crossorigin src="https://unpkg.com/react-dom@18/umd/react-dom.production.min.js"></script> <div id="root"></div>

Please try this code:请尝试以下代码:

const [currentNumber, setCurrentNumber] = useState(0);

useEffect(() => {
    if (currentNumber >= number) return;
    setTimeout(() => {
        setCurrentNumber(currentNumber + 1);
    }, 1000);
}, [currentNumber]);

return <span>{currentNumber}</span>;

I ran the code and it's getting stuck.我运行了代码,它卡住了。 Reason:原因:

You're scheduling 5 timers which will all update currentNumber to currentNumber + 1 .您正在安排 5 个计时器,它们都会将currentNumber更新为currentNumber + 1 currentNumber is 0 , so it will update number times to 1 after 2 seconds. currentNumber0 ,因此它将在 2 秒后将number次更新为1 You can approach this with an interval or a useEffect :您可以使用间隔或useEffect来解决此问题:

useEffect(() => {
  if (currentNumber < number)
    setTimeout(() => setCurrentNumber(n => n + 1), 2000)
}, [number, currentNumber])

If you're using an interval, make sure you return a cleanup callback from useEffect , like that:如果您使用间隔,请确保从useEffect返回清理回调,如下所示:

useEffect(() => {
  const id = useInterval(...)
  return () => clearInterval(id)
}, [...])

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