分组 python dataframe 并显示字典中每个唯一键的所有对应值

Question

I have the following dataset

id	date
7510	15 Jun 2020
7510	16 Jun 2020
7512	15 Jun 2020
7512	07 Jul 2020
7520	15 Jun 2020
7520	16 Aug 2020

I need to convert this to a dictionary which is quite straight forward, but need each unique id as a key and all corresponding values as values to the unique key.

for example; dictionary = {7510: ["15 Jun 2020", "16 Jun 2020"], 7512: ["15 Jun 2020", "07 Jul 2020"], 7520: ["15 Jun 2020", "16 Aug 2020"] }

Answer 1

Try this:

df.groupby('id')['date'].agg(list).to_dict()

Output:

{7510: ['15 Jun 2020', '16 Jun 2020'],
 7512: ['15 Jun 2020', '07 Jul 2020'],
 7520: ['15 Jun 2020', '16 Aug 2020']}