根据另一列获取每列的最小值

Question

Per each product_id based on the column year , I would like to get the value from column name that would represent the earliest name .

year	name	product_id	initial_name
2016	Pepsi.	123456	Pepsi.
2017	Pepsi co.	123456	Pepsi.
2017	Cola	567890	Cola
2018	Coca-Cola	567890	Cola
2019	Coca-Colas	567890	Cola

I started implementing the logic in this way but there must be an easier way:

SELECT *,
CASE WHEN year = date_min THEN name END name_min
FROM (
SELECT *,
    MIN(year) OVER (PARTITION BY product_id) year_min
FROM table

Answer 1

Use FIRST_VALUE() window function:

SELECT *,
       FIRST_VALUE(name) OVER (PARTITION BY product_id ORDER BY year) name_min
FROM tablename;