有人请帮我找出这段代码的错误

Question

What did I do wrong?

I haven't used string library function in this code. I just used index position of the string to solve this code. But when I submit it in URI, it's showing wrong ans. Can anyone help me, please!!

enter image description here

#include <stdio.h>

int main()
{
    int c, i, x;
    char s[10], r[10];
    scanf("%d", &x);

    for(i = 0, c = 0; i < x; i++){
        scanf("%s%s", s, r);
        c++;
        if(s[4] == 'a' && r[0] == 'l' || s[4] == 'a' && r[0] == 't'){
            printf("Caso #%d: Bazinga!\n", c);
        }
        else if(s[0] == 'l' && r[4] == 'a' || s[0] == 't' && r[4] == 'a'){
            printf("Caso #%d: Raj trapaceou!\n", c);
        }

        else if(s[0] == 'p' && r[4] == 'a' || s[0] == 'p' && r[0] == 's'){
            printf("Caso #%d: Bazinga!\n", c);
        }
        else if(s[4] == 'a' && r[0] == 'p' || s[0] == 's' && r[0] == 'p'){
            printf("Caso #%d: Raj trapaceou!\n", c);
        }

        else if(s[0] == 't' && r[0] == 'p' || s[0] == 't' && r[0] == 'l'){
            printf("Caso #%d: Bazinga!\n", c);
        }
        else if(s[0] == 'p' && r[0] == 't' || s[0] == 'l' && r[0] == 't'){
            printf("Caso #%d: Raj trapaceou!\n", c);
        }

        else if(s[0] == 'l' && r[0] == 's' || s[0] == 'l' && r[0] == 'p'){
            printf("Caso #%d: Bazinga!\n", c);
        }
        else if(s[0] == 's' && r[0] == 'l' || s[0] == 'p' && r[0] == 'l'){
            printf("Caso #%d: Raj trapaceou!\n", c);
        }

        else if(s[0] == 's' && r[0] == 't' || s[0] == 's' && r[4] == 'a'){
            printf("Caso #%d: Bazinga!\n", c);
        }
        else if(s[0] == 't' && r[0] == 's' || s[4] == 'a' && r[0] == 's'){
            printf("Caso #%d: Raj trapaceou!\n", c);
        }
        else if(s[4] == 'a' && r[4] == 'a' || s[0] == 'p' && r[0] == 'p' || s[0] == 't' && r[0] == 't' || s[0] == 'l' && r[0] == 'l' || s[0] == 's' && r[0] == 's'){
            printf("Caso #%d: De novo!\n", c);
        }

    }
}

Answer 1

Why don't you use the index [2] of s and r :

d: pedra
p: papel
s: tesoura
g: legarto
o: spock

Then the response would be

novo: 

s[2] == r[2]

bazinga:

s[2] == 's' && r[2] == 'p'
s[2] == 'p' && r[2] == 'd'
s[2] == 'd' && r[2] == 'g'
s[2] == 'g' && r[2] == 'o'
s[2] == 'o' && r[2] == 's'
s[2] == 's' && r[2] == 'g'
s[2] == 'g' && r[2] == 'p'
s[2] == 'p' && r[2] == 'o'
s[2] == 'o' && r[2] == 'd'
s[2] == 'd' && r[2] == 's'

trapaceou: otherwise.