Selenium 与 Python 3 - 如何单击元素

Question

I am new to Selenium I have been following the documentations but they seem outdated.

(for curious people, that is the admin section of Atlassian's Cloud https://admin.atlassian.com/s/orgID/users/userID , I wish to remove site access for multiple users)

Here is a subset of the HTML page:

<label data-size="regular" class="css-ji2l50" data-checked="true">
    <input name="" type="checkbox" value="123456789abcde">
        <span role="img" aria-label="check" class="css-zg81aj">
            <svg width="24" height="24" viewBox="0 0 24 24" role="presentation">
                <path d="M7.356 10.942a.497.497 0 00-.713 0l-.7.701a.501.501 0 00-.003.71l3.706 3.707a.501.501 0 00.705.003l7.712-7.712a.493.493 0 00-.006-.708l-.7-.7a.504.504 0 00-.714 0l-6.286 6.286a.506.506 0 01-.713 0l-2.288-2.287z" fill="currentColor"></path>
            </svg>
        </span>
        <span role="img" aria-label="cross" class="css-zg81aj">
            <svg width="24" height="24" viewBox="0 0 24 24" role="presentation">
                <path d="M15.185 7.4l-3.184 3.185-3.186-3.186a.507.507 0 00-.712.003l-.7.701a.496.496 0 00-.004.712l3.185 3.184L7.4 15.185a.507.507 0 00.004.712l.7.7c.206.207.516.2.712.004l3.186-3.185 3.184 3.185a.507.507 0 00.712-.004l.701-.7a.496.496 0 00.003-.712l-3.186-3.186 3.186-3.184a.507.507 0 00-.003-.712l-.7-.7a.508.508 0 00-.36-.153.5.5 0 00-.353.15z" fill="currentColor" fill-rule="evenodd"></path>
            </svg>
        </span>
</label>

I want to capture and click on <input name="" type="checkbox" value="123456789abcde">

Since there is no element = driver.find_element(By.VALUE,"123456789abcde") ( link to the documentation )
I am using element = driver.find_element(By.XPATH, "//input[@value='123456789abcde']")

This seems to work fine, print(element) gives <selenium.webdriver.remote.webelement.WebElement (session="b2d92d7e20334085b7989c009fa77785", element="c23fdd99-9052-4028-9a72-e8f39873c720")>

But element.click() results in a ElementClickInterceptedException exception. element.click does return <bound method WebElement.click of <selenium.webdriver.remote.webelement.WebElement (session="b2d92d7e20334085b7989c009fa77785", element="c23fdd99-9052-4028-9a72-e8f39873c720")>> but the button is not toggled.

What am I doing wrong? Note that I am using Edge webdriver if that matters.

Thanks.

EDIT: From first investigations, it seems that the the <label> is overlapping the input. If I indeed click on the label itself it does toggle the button. In the page code above, I tested my code on the xpath driver.find_element(By.XPATH, "//label[@data-checked='true']").click() but the thing is that there are several labels on the page that show a data-checked='true' property. How to craft the xpath so that I select the label associated with that specific input. Basically mixing the "//label[@data-checked='true']" and //input[@value='123456789abcde'] xpaths.

Answer 1

Since we have no access to that page we can only guess.
So, instead of driver.find_element(By.XPATH, "//input[@value='123456789abcde']").click() Try adding a wait. The WebdriverWait is the preferred way to do that, as following:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

wait = WebDriverWait(driver, 20)

wait.until(EC.element_to_be_clickable((By.XPATH, "//input[@value='123456789abcde']"))).click()

UPD
In case you need to click the label element which is a direct parent of this input the locator can be updated as following:

wait.until(EC.element_to_be_clickable((By.XPATH, "//input[@value='123456789abcde']/.."))).click()

Another way to precisely locate that label is to find the parent div based on the child input and from it to get the child label as following:

wait.until(EC.element_to_be_clickable((By.XPATH, "//div[.//input[@value='123456789abcde']]//label"))).click()