Python 从 n 元素中获取字符到最后包含的最后一个
[英]Python get character from n element to last included last
问题描述
link_element = """a target="_top" aria-current="false" class="Anchor NavList__Anchor" href="/tr/turnuva-konumu/y%C3%BCksek-oran/101/d%C3%BCnya/240/sk-slavia-prague-rak%C3%B3w-cz%C4%99stochowa-hnk-hajduk-split-villarreal-cf-cfr-cluj-nk-maribor-%C5%A1k-slovan-bratislava-h%C5%A1k-zrinjski-mostar/***180254557458746932***">xxx</a"""
uniqueid = link_element['href'][-18:-1]
When i try to get the integer value of the link it returns with bs4 and requests libs 18025455745874693.It does not include the last char.
当我尝试获取链接的 integer 值时，它使用 bs4 返回并请求库 18025455745874693。它不包括最后一个字符。 How can i get the full integer value of the href?如何获得完整的 integer 值？
1 个解决方案
解决方案1
2 2022-09-02 13:32:06
In this case you can just replace [-18:-1] with [-18:] .在这种情况下，您只需将[-18:-1]替换为[-18:]即可。 Using -1 as your ending index excludes the last character.使用-1作为结束索引会排除最后一个字符。
However, in the case where this ID's length is variable (ie. may not always be 18 characters), the better option would be to split your string by / and grab the last element.但是，如果此 ID 的长度是可变的（即，可能并不总是 18 个字符），更好的选择是用/分割字符串并获取最后一个元素。
unique_id = link_element['href'].split("/")[-1]
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.