简体   繁体   English

Python:根据多个键值过滤字典列表

[英]Python: filter list of dictionaries based on multiple key values

I am importing a log file with JSON-like dictionaries and attempting to: 1)only include logs where all three keys are included 2)create a new list of dictionaries that only have these key/values我正在使用类似 JSON 的字典导入日志文件并尝试:1)仅包含包含所有三个键的日志 2)创建仅包含这些键/值的新字典列表

log:日志:

{"pytest_version": "7.1.e", "$report_type": "SessionStart"}
{"label": "test1", "outcome": "passed", "duration":0.0009}
{"label": "test2", "outcome": "passed", "duration":0.00019}

Script:脚本:

with open('log', 'r') as f:
    key_list = ['label', 'outcome']
    l = [json.loads(log) for log in logs]
    l2 = [{k:v for k, v in d.items() if k in key_list} for d in l]
    print(l2)

Output Output

 [{},
 {'label': 'test1', 'outcome': 'passed'},
 {'label': 'test2', 'outcome': 'passed'}]

Why is there an empty dictionary in the results?为什么结果中有一个空字典? And how could it be modified to only include results if the key has a value (eg exclude 'outcome':'' )如果键有值(例如排除'outcome':'' ),如何修改它以仅包含结果

The first empty dictionary {} is there because {"pytest_version": "7.1.e", "$report_type": "SessionStart"} doesn't contain key 'label' or 'outcome' .第一个空字典{}在那里,因为{"pytest_version": "7.1.e", "$report_type": "SessionStart"}不包含键'label''outcome'

One solution might be using all() to keep only the dictionaries which contains all keys in the key_list :一种解决方案可能是使用all()仅保留包含key_list所有键的字典:

logs = [
    {"pytest_version": "7.1.e", "$report_type": "SessionStart"},
    {"label": "test1", "outcome": "passed", "duration": 0.0009},
    {"label": "test2", "outcome": "passed", "duration": 0.00019},
]

key_list = ["label", "outcome"]

print(
    [{k: d[k] for k in key_list} for d in logs if all(k in d for k in key_list)]
)

Prints:印刷:

[{'label': 'test1', 'outcome': 'passed'}, {'label': 'test2', 'outcome': 'passed'}]

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM