如何在文件中的固定数量的字符后插入新的行字符

Question

我正在寻找一个bash或sed脚本（最好是一行代码），我可以在巨大的文本文件中使用固定数量的字符后插入一个新行字符。

Answer 1

How about something like this? Change 20 is the number of characters before the newline, and temp.text is the file to replace in..

sed -e "s/.\{20\}/&\n/g" < temp.txt

Answer 2

Here is POSIX solution:

awk '{gsub(/.{5}/,"&\n")}1' file

Or:

fold -w5 file

Input:

banana strawberry grape

Output:

banan
a str
awber
ry gr
ape

Interestingly, the Awk solution is more performant than fold.

Answer 3

Let N be a shell variable representing the count of characters after which you want a newline. If you want to continue the count accross lines:

perl -0xff -pe 's/(.{'$N'})/$1\n/sg' input

If you want to restart the count for each line, omit the -0xff argument.

Answer 4

Because I can't comment directly (to less reputations) a new hint to upper comments:

I prefer the sed command (exactly what I want) and also tested the Posix-Command fold . But there is a little difference between both commands for the original problem: If you have a flat file with n*bytes records (without any linefeed characters) and use the sed command (with bytes as number (20 in the answer of @Kristian)) you got n lines if you count with wc . If you use the fold command you only got n-1 lines with wc ! This difference is sometimes important to know, if your input file doesn't contain any newline character, you got one after the last line with sed and got no one with fold

Answer 5

if you mean you want to insert your newline after a number of characters with respect to the whole file, eg after the 30th character in the whole file

gawk 'BEGIN{ FS=""; ch=30}
{
    for(i=1;i<=NF;i++){
        c+=1
        if (c==ch){
            print "" 
            c=0           
        }else{
            printf $i
        }
    }
    print ""
}' file

if you mean insert at specific number of characters in each line eg after every 5th character

gawk 'BEGIN{ FS=""; ch=5}
{
    print substr($0,1,ch) "\n" substr($0,ch)
}' file

Answer 6

Append an empty line after a line with exactly 42 characters

sed -ie '/^.\{42\}$/a\
' huge_text_file

Answer 7

This might work for you:

echo aaaaaaaaaaaaaaaaaaaax | sed 's/./&\n/20'
aaaaaaaaaaaaaaaaaaaa
x