[英]How to create a rhomboid in pygame
I want to create a rhomboid like this.我想创建一个像这样的菱形。 I can not do this I found the solution just for the diamond.我无法做到这一点,我只为钻石找到了解决方案。
my code:我的代码:
import pygame as pg
pg.init()
screen = pg.display.set_mode((500, 700))
clock = pg.time.Clock()
BG_COLOR = pg.Color('gray12')
BLUE = pg.Color('dodgerblue')
points = [(200, 200), (250, 250), (200, 300), (150, 250)]
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
screen.fill(BG_COLOR)
pg.draw.polygon(screen, BLUE, points)
pg.display.flip()
clock.tick()
Write a function that draws a rhomboid with a with
, height
and offset:编写一个 function 来绘制一个带有with
、 height
和 offset 的菱形:
import pygame as pg
def drawRhomboid(surf, color, x, y, width, height, offset, thickness=0):
points = [
(x + offset, y),
(x + width + offset, y),
(x + width, y + height),
(x, y + height)]
pg.draw.polygon(surf, color, points, thickness)
pg.init()
screen = pg.display.set_mode((500, 700))
clock = pg.time.Clock()
BG_COLOR = pg.Color('gray12')
BLUE = pg.Color('dodgerblue')
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
screen.fill(BG_COLOR)
drawRhomboid(screen, BLUE, 50, 50, 300, 200, 100, 3)
pg.display.flip()
clock.tick()
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