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使用 Golang 解组 JSON 字符串

[英]Unmarshalling JSON string with Golang

I have the following json string我有以下 json 字符串

{"x":{"la":"test"}} {"x":{"la":"test"}}

type Object struct {
    Foo  map[string]map[string]string `json:"l.a"`
    }
     var obj Object
    err = json.Unmarshal(body, &obj)
    if err != nil{
        fmt.Println(err)
    }
    fmt.Println("jsonObj", obj)

but get empty any idea how can i get the string "test"但是让空任何想法我怎样才能得到字符串“test”

With your code Unmarshal is looking for la at the top level in the JSON (and it's not there - x is).使用您的代码, Unmarshal正在 JSON 的顶层寻找la (它不存在 - x存在)。

There are a number of ways you can fix this, the best is going to depend upon your end goal;有很多方法可以解决这个问题,最好的方法取决于你的最终目标; here are a couple of them ( playground )这里有几个(操场

const jsonTest = `{"x":{"l.a":"test"}}`

type Object struct {
    Foo map[string]string `json:"x"`
}

func main() {
    var obj Object
    err := json.Unmarshal([]byte(jsonTest), &obj)
    if err != nil {
        fmt.Println(err)
    }
    fmt.Println("jsonObj", obj)

    var full map[string]map[string]string
    err = json.Unmarshal([]byte(jsonTest), &full)
    if err != nil {
        fmt.Println(err)
    }
    fmt.Println("jsonObj2", full)

}

(Got a phone call while entering this and see @DavidLilue has provided a similar comment but may as well post this). (输入此内容时接到电话,请参阅@DavidLilue 提供了类似的评论,但不妨发布此内容)。

You can always create a struct to unmarshall your json您始终可以创建一个结构来解组您的 json

type My_struct struct {
    X struct {
        LA string `json:"l.a"`
    } `json:"x"`
}

func main() {
    my_json := `{"x":{"l.a":"test"}}`
    var obj My_struct
    json.Unmarshal([]byte(my_json), &obj)
    fmt.Println(obj.X.LA)
}

here you are creating a struct and then unmarshalling your json string to its object, so when you do obj.X.LA you will get the string在这里,您正在创建一个结构,然后将您的 json 字符串解组为其 object,因此当您执行obj.X.LA时,您将获得该字符串

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