正则表达式以

Question

With python I want to use regular expression(or any other way) to find all strings between

£ and £ 
$ and $ 
[ and ]

sample_text = "All £blocker£ §YTile Blockers§! have been cleared from $country$ $status$ [From.From.GetName]."

With this sample text I want to get output of

blocker
country
status
From.From.GetName

Answer 1

Use re.findall :

# -*- coding: utf-8 -*-
import re

sample_text = "All £blocker£ §YTile Blockers§! have been cleared from $country$ $status$ [From.From.GetName]."
matches = re.findall(r'[£§$\[](.*?)[£§$\]]', sample_text)
print(matches)  # ['blocker', 'YTile Blockers', 'country', 'status', 'From.From.GetName']

The regex pattern used here says to match:

• [£§$\[] match an opening marker
• (.*?) match and capture in \1 the content
• [£§$\]] then match a closing marker

Answer 2

([£§$])(\S*)\1 can exclude spaces.

Answer 3

Here is a solution without regular expression. It requires to implement a simple parsing function, apply it to the tokenized text and finally filter the results to exclude the None values.

def parse(word):
    symbols = ['£', '$', '[]']
    for s in symbols:
        _len = len(s)
        if _len == 1:
            start = word.find(s)
            end =  word[start+1:].find(s)
            if start != -1 and end != -1:
                return word[start+1:start+end+1]
        elif _len == 2:
            start = word.find(s[0])
            end =  word[start+1:].find(s[-1])
            if start != -1 and end != -1:
                return word[start+1:start+end+1]
        
sample_text = "All £blocker£ §YTile Blockers§! have been cleared from $country$ $status$ [From.From.GetName]."

result = list(filter(None, map(parse, sample_text.split(' '))))
print(result) #['blocker', 'country', 'status', 'From.From.GetName']