将 function 附加到 React 中的功能组件

Question

Have a child component which is

const Block = () => {}

Block.onClick = (props) => {
  return true/false
} 

Block.onSpan = () => {
  return true/false
}

We have a parent, let's call it DaddyBlock

<DaddyBlock customBlock={Block || undefined} />


const DaddyBlock = ({customBlock}) => {
   if(customBlock){
     handleClick = () => {/where we use result from customBlock.canClick/}
     handleSpan = () => {/where we use result from customBlock.canSpan/}
     const CustomBlock = customBlock;
     return <CustomBlock handleClick={handleClick} handleSpan={handleSpan} {...props} />
   }
   return <DefaultBlock />
}

Answer 1

I don't think that there is actually a real relevance to do it like that. If you would use TypeScript for instance, you would make typing of this part of the code harder and there are actually other "reserved" properties that are used by React, eg "propTypes" or "displayName". That is the reason why you shouldn't do it, as you did it.

Another approach just for grouping these kind of elements that is more clean is the following:

Block.Component = () => {}

Block.onClick = (props) => {
  return true/false
} 

Block.onSpan = () => {
  return true/false
}

Now you are not attaching the properties to the component that is used by React internally, but still have the grouping and flexibility you need.