[英]When converting an int to a hex, do we have to convert it to a string or can we keep it a type int? c++
For this Systems I class that I'm in, they are wanting us to take in a number and convert it to hex.对于我所在的系统 I class,他们希望我们输入一个数字并将其转换为十六进制。 I know that I can do it this way:我知道我可以这样做:
cin >> std::hex >> x;
But for this program, I want to try and do it after, because of an if
statement.但是对于这个程序,我想在之后尝试做,因为有一个if
语句。
Here is the code that I have.这是我拥有的代码。
cout << "Enter an integer value between 0 and 255 for Green: ";
cin >> G;
if (G > 255 || G < 0)
{
cout << "The number you have entered is bigger than 255 or smaller than 0.";
}
else
{
G = std::hex >> G;
}
Take in a number and convert it to hex.输入一个数字并将其转换为十六进制。
This satisfies the ask.这满足了要求。 Reads the decimal number (0 to 255), stores it in an integer.读取十进制数(0 到 255),将其存储在 integer 中。 Uses the integer to display both decimal and hex formatting of the value entered.使用 integer 显示输入值的十进制和十六进制格式。
#include <iostream>
int main() {
int G;
while (true)
{
std::cout << "Enter an integer value between 0 and 255 for Green: ";
std::cin >> G;
if (G > 255 || G < 0)
{
std::cout << "The number you have entered is bigger" \
<< " than 255 or smaller than 0.\n";
}
else
{
break;
}
}
std::cout<< "G is " << G << " in decimal and 0x" << std::hex << G << " in hex.\n";
}
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