[英]select all sales from specific day ? mysql , convert datetime to date
how to convert the DateTime column to date?如何将 DateTime 列转换为日期?
I need something like the select * from sales where date = = "2022-09-18";
我需要类似
select * from sales where date = = "2022-09-18";
I need to get all sales from a specific day我需要获得特定日期的所有销售额
I tried this How can I convert datetime to date, truncating the times, leaving me the dates?我试过这个如何将日期时间转换为日期,截断时间,给我留下日期? and many more solutions but nothing is working.
还有更多解决方案,但没有任何效果。
i tried this SELECT DATE(
datatime ) AS date_of_booking FROM sales; ";
我试过这个
SELECT DATE(
) AS date_of_booking FROM sales; ";
) AS date_of_booking FROM sales; ";
but it gave me this ) AS date_of_booking FROM sales; ";
但它给了我这个
I tried also this but it gave me error this我也试过这个,但它给了我这个错误
this is a table named Sales
这是一个名为
Sales
的表
if there is anybody that can help me understand how do I get this thing to work please i really appreciate that.如果有人可以帮助我了解如何让这件事发挥作用,我真的很感激。 a lot .
很多 。
code for generating the database if you want如果需要,用于生成数据库的代码
DROP DATABASE IF EXISTS ice_cream_store;
CREATE DATABASE IF NOT EXISTS ice_cream_store;
USE ice_cream_store;
CREATE TABLE `Tastes` (
`tid` INTEGER NOT NULL AUTO_INCREMENT primary key,
`name` VARCHAR(20) NOT NULL,
UNIQUE (name)
);
CREATE TABLE `Toppings` (
`topid` INTEGER NOT NULL AUTO_INCREMENT primary key,
`name` VARCHAR(20) NOT NULL,
UNIQUE (name)
);
CREATE TABLE `Receptacles` (
`rid` INTEGER NOT NULL AUTO_INCREMENT primary key,
`name` VARCHAR(20) NOT NULL,
`price` int NOT NULL,
UNIQUE (name)
);
CREATE TABLE `Sales` (
`sid` INTEGER NOT NULL AUTO_INCREMENT primary key,
`rid` integer not null,
foreign key (`rid`) references Receptacles(`rid`),
`datetime` datetime not null,
`completed` bool not null,
`paid` bool not null,
`total_price` INTEGER NOT NULL
);
CREATE TABLE `Tastes_Sales` (
`sid` integer not null,
foreign key (`sid`) references Sales(`sid`),
`tid` integer not null,
foreign key (`tid`) references Tastes(`tid`),
PRIMARY KEY (`sid` , `tid`),
`quantity` integer not null
);
CREATE TABLE `Toppings_Sales` (
`sid` integer not null,
foreign key (`sid`) references Sales(`sid`),
`topid` integer not null,
foreign key (`topid`) references Toppings(`topid`),
PRIMARY KEY (`sid` , `topid`)
);
SELECT
DATE(`datatime`)
AS date_of_booking
FROM sales;
select * from tastes;
select * from Receptacles;
select * from Toppings;
select * from sales;
select * from Toppings_Sales;
select * from Tastes_Sales;
Use the extract function使用提取物 function
Example:例子:
SELECT EXTRACT(MONTH FROM "2017-06-15 09:34:21");
outputs 6输出 6
From there you just do:从那里你只需:
select * from sales where EXTRACT(DAY FROM date) = 18;
Now you just add AND operators to do the same for month and year现在您只需添加 AND 运算符即可对月份和年份执行相同的操作
I think this is a simple enough solution.我认为这是一个足够简单的解决方案。 Hope this works for you.
希望这对你有用。
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