如何将浮点数增加一定数量但仍始终保持在 1 以下？

Question

floats = [0.3, 0.45, 0.98, 0.01]

I have a list of floats in the range of 0<n<1. For certain numbers, for example, 0.98, I want to increase it so that it is even larger compared to other numbers. For example, I can increase it by multiplying with a co-efficient >1. For example:

a = 1.4*0.98

But this makes 'a' exceed 1. I want to keep 'a' still in the range of 0<a<1, for example, 0.995. Is there a way to do that?

Answer 1

For arguments sake lets's say that we want to repeatedly uplift each value by some factor. Let that factor be 10% of the difference between the value and 1. Let's do this repeatedly:

floats = [0.3, 0.45, 0.98, 0.01]

for _ in range(100):
    floats = [(1 - v) * 0.1 + v for v in floats]

print(floats)

Output:

[0.9999814070207786, 0.9999853912306118, 0.9999994687720222, 0.9999737042151013]

Thus all values tend towards 1 but never* get there.

*At some point I guess you could come to a point where this algorithm makes no change to the original value. The uplift factor would therefore need to be adjusted (maybe 1% or even less) depending on how often this is going to happen