[英]fp-ts how to prevent traverse from short circuit on Either left?
I have the following code:我有以下代码:
const tError = (err) => (err instanceof Error ? err : Error("unexpected error"));
const safeImport = TE.tryCatchK((s) => import(s)),tError);
export const run= (globString) => pipe(
glob.sync(globString),
TE.traverseArray(safeImport),
async x => console.log(await x()),
)
//this call outputs
[{_tag: 'Left', left: Error [ERR_MODULE_NOT_FOUND]: Cannot find module...}]
but if I do:但如果我这样做:
const tError = (err) => (err instanceof Error ? err : Error("unexpected error"));
const safeImport = TE.tryCatchK((s) => import(s)),tError);
export const run= (globString) => pipe(
glob.sync(globString),
A.map(safeImport),
A.map(async x => console.log(await x())),
)
//this call outputs
[
{_tag: 'Left', left: Error [ERR_MODULE_NOT_FOUND]: Cannot find module...},
{_tag: 'Right', right:...},{_tag: 'Right', right:...},{_tag: 'Right', right:...},{_tag: 'Right', right:...}
]
//
I would like to flip the types but keeping both the left and the rights, any idea of what I am doing wrong?我想翻转类型,但同时保留左侧和右侧,知道我做错了什么吗?
So, the way to do this is by not using an TE.traverseArray
but T.traverseArray
:因此,这样做的方法是不使用
TE.traverseArray
而是使用T.traverseArray
:
const tError = (err) => (err instanceof Error ? err : Error("unexpected error"));
const safeImport = TE.tryCatchK((s) => import(s)),tError);
export const run= (globString) => pipe(
glob.sync(globString),
T.traverseArray(safeImport),
async x => console.log(await x()),
)
That will remove the Task wrapper and keep the eithers as elements of the array.这将删除 Task 包装器并将其保留为数组的元素。
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