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如何在 groovy 中的现有节点 Xml 中添加节点列表

[英]How to add list of Nodes in existing Node Xml in groovy

I have such a XML structure, with list of 'attachments', and I want iterate incoming List<String> files and create a groovy.util.Node for each of them and then return the builded Node.我有这样一个 XML 结构,带有“附件”列表,我想迭代传入的List<String> files并为每个文件创建一个 groovy.util.Node,然后返回构建的节点。 In code below I use only the fist element from list(base64 file), but I want to create attachments dynamically based on array size.在下面的代码中,我仅使用列表(base64 文件)中的第一个元素,但我想根据数组大小动态创建attachments I am new in groovy and can't find the way how to expand the Node properly.我是 groovy 的新手,找不到正确扩展节点的方法。

import groovy.abi.XML

class TestService {

    Node buildNode(List<String> files) {
        Node node = XML.builder().
                "sab:sendExternalEmail"("xmlns:sab": "http://sab/") {
                    "sab:to"('client@gmail.com')
                    "sab:subject"('Reply')
                    "sab:body"('Body')
                    "sab:from"('sender@gmail.com')
                    "sab:attachments"() {
                        "sab:attachment"() {
                            "sab:fileName"('file1')
                            "sab:fileBase64"(files[0])
                        }
                    }
                }
    }
}

just to gibe you an idea how to work with builders:只是为了让您了解如何与建设者合作:

import groovy.util.NodeBuilder
import groovy.xml.XmlUtil


def attachments = [
    "name 1": "content 1",
    "name 2.txt": "content 2"
]

def xml = new NodeBuilder().a{
  for(a in attachments){
    attacchment{
      fileName(a.key)
      fileBase64(a.value)
    }
  }
}

println XmlUtil.serialize(xml)

result:结果:

<?xml version="1.0" encoding="UTF-8"?><a>
  <attacchment>
    <fileName>name 1</fileName>
    <fileBase64>content 1</fileBase64>
  </attacchment>
  <attacchment>
    <fileName>name 2.txt</fileName>
    <fileBase64>content 2</fileBase64>
  </attacchment>
</a>

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