在原始数组的条件下创建具有不同数据结构的新数组的最佳实践是什么？

Question

assume I have an array as my origin data set

const users = [
{id: 1, name: 'userOne', age: 23, licenseNumber: '95273380'},
{id: 2, name: 'userTwo', age: 21, licenseNumber: '95273381'},
{id: 3, name: 'userThree', age: 18, licenseNumber: ''},
{id: 4, name: 'userFour', age: 2, licenseNumber: '95273382'},
{id: 5, name: 'userFive', age: 77, licenseNumber: null},
{id: 6, name: 'userSix', age: 35, licenseNumber: '95273383'},
]

and now I want to create an new array base on it by conditions and with a new data structure

1. need to filter all users if liscenNumber is empty or null.
2. create key value pair return (licenseNumber as key, name as value)

(So far i tried filiter() method, But is only handle conditions, there no way i can custom a new data structure to return)

Answer 1

Here you are, you can just use filter to filter - then map to build your new array.

 const users = [ { "id": 1, "name": "userOne", "age": 23, "licenseNumber": "95273380" }, { "id": 2, "name": "userTwo", "age": 21, "licenseNumber": "95273381" }, { "id": 3, "name": "userThree", "age": 18, "licenseNumber": "" }, { "id": 4, "name": "userFour", "age": 2, "licenseNumber": "95273382" }, { "id": 5, "name": "userFive", "age": 77, "licenseNumber": null }, { "id": 6, "name": "userSix", "age": 35, "licenseNumber": "95273383" } ] const result = users.filter(x => x.licenseNumber).map(x => ({[x.licenseNumber]: x.name})); console.log(result);