[英]Check a list contains given elements
I want to check if my list's first four elements are digits.我想检查我的列表的前四个元素是否是数字。 what i did is as follows:
我所做的如下:
myList = ['0', '3', '2', '7', 'O', 'K', 'P']
if myList[0:4] in string.digits:
print('okay')
else:
print('wrng')
But this gives the following error.但这会产生以下错误。
TypeError: 'in <string>' requires string as left operand, not list
How can I achieve this?我怎样才能做到这一点?
The error is telling you that you can't do some_list in some_string
- after all, a list consists of characters, not lists, so it's pointless.该错误告诉您不能在
some_list in some_string
- 毕竟,列表由字符组成,而不是列表,因此毫无意义。 You want to check if all the characters in your list are in the string, so:您想检查列表中的所有字符是否都在字符串中,因此:
if all(ch in string.digits for ch in myList[:4]):
The 0
in 0:4
is not needed, it's the default. 0
0:4
中的 0 不需要,它是默认值。
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