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如果存在密钥,如何在 mongoDB 多个条件中应用

[英]how apply in mongoDB multiple conditions if key exist

const filterOptions = {
        carColor: req.query.carColor, 
        languages: { $regex: `${req.query.languages}`, $options: 'i' },
        incomeMonth: { $gte: req.query.incomeMonth },
        incomeYear: { $gte: req.query.incomeYear },
        age: { $gte: query.fromAge, $lt: query.toAge }, // age from - to
        familyStatus: query.familyStatus
    }

    const profiles = await Profile.find(filterOptions)
        .sort({ createdAt: 1 })
        .limit(100)

    return res.json({ success: true, count: profiles?.length, profiles })

for example I have multiple query, and one of theme language key: req.query.language, and I wanna apply only for this query key $regex method, otherwise if empty key for any, I don't wanna pass it into find() method例如我有多个查询,主题语言键之一:req.query.language,我只想申请这个查询键 $regex 方法,否则如果任何键为空,我不想将它传递给 find( ) 方法

You should fill the filterOptions object, conditionally, only for keys that exist.您应该有条件地填写filterOptions object,仅针对存在的键。

let filterOptions = {};
if (req.query.carColor) {
  filterOptions =  {...filterOptions, carColor: req.query.carColor};
} 
if (req.query.languages) {
  filterOptions =  {...filterOptions, languages: { $regex: `${req.query.languages}`, $options: 'i' }};
}
if (req.query.incomeMonth) {
  filterOptions =  {...filterOptions, incomeMonth: { $gte: req.query.incomeMonth }};
}
if (req.query.incomeYear) {
  filterOptions =  {...filterOptions, incomeYear: { $gte: req.query.incomeYear }};
}
if (req.query.fromAge && req.query.toAge) {
  filterOptions =  {...filterOptions, age: { $gte: query.fromAge, $lt: query.toAge }};
}
if (req.query.filmStatus) {
  filterOptions =  {...filterOptions, familyStatus: query.familyStatus};
}

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