React Native - 如何合并用户项目并显示在他的个人资料上？

Question

What i have:

{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-2", "slug": {"_type": "slug", "current": "author-2-slug"}}
{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-3", "slug": {"_type": "slug", "current": "author-3-slug"}}

What i want:

{"name": "author-2", "slug": {"_type": "slug", "current": "author-2-slug"}}
{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-3", "slug": {"_type": "slug", "current": "author-3-slug"}}

What i tried:

const filtered = _.uniqBy(authors, 'slug')

//result [], [], [], []

Any solution?

Answer 1

If this is lodash function, you shoud try like this, if you don't want to have 2 same authors:

const filtered = _.uniqBy(authors, 'name')

Answer 2

const uniqueTags = []; authors.map((item) => { var findItem = uniqueTags.find((x) => x.name === item.name); if (!findItem) uniqueTags.push(item); });