[英]SQL Basic: Group by function
I am trying to get a table that would outline two group by functions but having some minor difficulty.我正在尝试获得一个按功能概述两组但有一些小困难的表格。
select
to_char("CreateTime", 'YYYY-MM') as MonthYear,
floor(sum("Time"))::integer / 60 as "#MinutesWorkouts",
sum(case when "Type" = 29 then 1 else 0 end) as "#Streaming",
(sum(case when "Type" = 29 then "Time" else 0 end))::integer / 60 as "StreamingMinutes",
sum(case when "Type" = 9 then 1 else 0 end) as "#GuidedProgram",
sum(case when "Type" = 28 then 1 else 0 end) as "#Tall"
from
match_history
WHERE
"MachineId" = {{Machine_Id}}
GROUP by
to_char("CreateTime", 'YYYY-MM')
Ideally - I'd like to showcase Machine ID in the column along with the dates.理想情况下 - 我想在列中展示机器 ID 以及日期。 Currently the result shows as (image link) as it only shows the monthyear as the group function.目前结果显示为(图片链接),因为它仅将月份显示为组 function。 I would like to ensure it shows machine ID on the column too as I'd like to add multiple machine IDs.我想确保它也在列上显示机器 ID,因为我想添加多个机器 ID。
Why not just add machine_id?为什么不只添加 machine_id?
select
to_char("CreateTime", 'YYYY-MM') as MonthYear,
"MachineId",
floor(sum("Time"))::integer / 60 as "#MinutesWorkouts",
sum(case when "Type" = 29 then 1 else 0 end) as "#Streaming",
(sum(case when "Type" = 29 then "Time" else 0 end))::integer / 60 as "StreamingMinutes",
sum(case when "Type" = 9 then 1 else 0 end) as "#GuidedProgram",
sum(case when "Type" = 28 then 1 else 0 end) as "#Tall"
from
match_history
GROUP by
to_char("CreateTime", 'YYYY-MM'), "MachineId"
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