如何将浮点数格式化为 x 有效数字

Question

I am looking to print a floating-point number to a number of significant digits, where I consider digits in front of the decimal separator as significant. So with 3 significant digits, I would like the following:

1234.56 --> 1234
123.456 --> 123
12.3456 --> 12.3
1.23456 --> 1.23
.123456 --> 0.123
.012345 --> 0.0123
.0012345 --> 0.00123

Basically, I want to suppress the decimal fraction if it is not required, but I do not want to round the integer part. (And I would like to avoid scientific notation.)

How can I achieve that? I tried a number of ways, but none really do what I want.

This is close, but uses scientific notation:

for x in [1234.56, 123.456, 12.3456, 1.23456, .123456, .012345, .0012345]:
    print(x, " --> ", f"{x:.3g}")

1234.56  -->  1.23e+03  # wrong!
123.456  -->  123
12.3456  -->  12.3
1.23456  -->  1.23
0.123456  -->  0.123
0.012345  -->  0.0123
0.0012345  -->  0.00123

Answer 1

In such conditions you can try like this

for f in [1234.56, 123.456, 12.3456, 1.23456, .123456, .012345, .0012345]:

    dp= str(f)[::-1].find('.')
    #print(dp)
    if dp <=3:

        fs= int(f)
        print(f, "-->",fs)
    else:
        print(f, " --> ", f"{f:.3g}")

output:

1234.56 --> 1234
123.456 --> 123
12.3456  -->  12.3
1.23456  -->  1.23
0.123456  -->  0.123
0.012345  -->  0.0123
0.0012345  -->  0.00123