如何正确地创建一个条件，一旦条件满足就会退出 while 循环？

Question

import random as r

print(
"""
        Welcome to the Custom Counter!
    
    Type in your starting value and your
    ending value. Then, enter the amount
    by which to count.
""")

x = True

start = int(input("Starting number: "))
while x != False or start != "":
    fin = int(input("Ending number: "))
    amount = int(input("Count by: "))
    if amount > 0 or amount < 0:
        x = False
        
result = r.randrange(start, fin, amount)    
print(result)

input("Hit enter to exit.")

I made the while loop in hopes to exit the program when you clicked enter. Unfortunately, this will not let me exit the while loop no matter what I do. I am a noob at python. What is wrong with my condition?

Thank you!

Answer 1

Welcome to stackoverflow and welcome to Python!

Try to use and instead of or .

In your line:

while x != False or start != "":

You say to python, you want to run until 1st or 2nd condition is true. Since the 2nd condition stays always true, while will run forever.

Even more simple:

while x and start:

Hope you will enjoy Python as I do!

Answer 2

my code:

import random as r

print(
"""
        Welcome to the Custom Counter!
    
    Type in your starting value and your
    ending value. Then, enter the amount
    by which to count.
""")


while True:
    
    try:
        start = int(input("Starting number: "))
        fin = int(input("Ending number: "))
        amount = int(input("Count by: "))
    
    except ValueError as verr:
        
        print('error : ', verr,'\n restarting ....')
        
    else:
        
        break
        
   
result = r.randrange(start, fin, amount)    
print('result : ' ,result)

input("Hit enter to exit.")

this one I believe takes into account inputting of non int s and restart program from scratch when encountering such kind of inputs.

See The try statement specifies exception handlers and/or cleanup code for a group of statements

PS your code doesnt handle invalid values (ie fin < start )