之后如何制作 Tkinter 表和小部件？

Question

I am trying to make a table in Tkinter, and that works just fine. However, any widgets that are packed after the table are not generated and instead throw an error. How can I fix this?

This is the table code:

class Table:
  def __init__(self,root,rows,columns,lst):
    for i in range(rows):
      for j in range(columns):
        self.e = Entry(root, width=20, font=('Arial',16,))
        self.e.grid(row=i, column=j)
        self.e.insert(END, lst[i][j])

This is the table generating code and after:

    thislist = [
      ("Title", name),
      ("Company Size", vol),
      ("Price per share", price)
    ]
    row_amount = 3
    col_amount = 2
    Table(root1, row_amount, col_amount, thislist)
    color = 'red' if percent < 0 else 'green' if percent > 0 else 'gray'
    Label(root1, text = str(percent) + '%', fg = color).pack()

And this is the error:

Exception in Tkinter callback
Traceback (most recent call last):
  File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/tkinter/__init__.py", line 1892, in __call__
    return self.func(*args)
  File "main.py", line 77, in search_function
    layout(name.upper())
  File "main.py", line 105, in layout
    Label(root1, text = str(percent) + '%', fg = color).pack()
  File "/nix/store/2vm88xw7513h9pyjyafw32cps51b0ia1-python3-3.8.12/lib/python3.8/tkinter/__init__.py", line 2396, in pack_configure
    self.tk.call(
_tkinter.TclError: cannot use geometry manager pack inside . which already has slaves managed by grid

Answer 1

The error obviously tells you that you have use both .grid() (all entry widgets inside Table class) and .pack() (label showing percentage) inside same parent container root1 which is not allowed.

Suggest to put those entry widgets inside a frame instead and then pack this frame using .pack() :

...
    # frame to hold the table
    frame = Frame(root1)
    frame.pack()
    # create table inside frame
    Table(frame, row_amount, col_amount, thislist)
    color = 'red' if percent < 0 else 'green' if percent > 0 else 'gray'
    Label(root1, text = str(percent) + '%', fg = color).pack()
...