遍历压缩在文件夹中的特定文件，并根据在 Python 中找到的文本/字符串移动它们

Question

I have multiple zipped files that I need to identify a string within the specific.html. All of the.html that I need to read end with the last 7 characters of 'bb.html'.

My goal is to move the whole.zip file if the html within contains the string/word.

I have this code written which works on the file that is listed but I need to iterate through thousands of zipped files. It doesn't have to be written as a function.

import os
import zipfile

        def check_files():
            os.listdir(source_folder)
            zip = zipfile.ZipFile(source_file3)
            file = zip.read("bb.html")
            if b'word' in file:
                shutil.copy(source_file3, source_folder2)
                print('word found-file moved')
            else:
                print('word not found')

most of the help I find iterates over the files inside, I need to iterate over ALL the.zip files and read into each bb.html file only.

I am new to Python so I have that as a challenge as well.

Thanks in advance.

Thanks so much for the answers:!!! FINAL CODE:

    source_file3 = ('C:/Users/SMITH/Desktop/zipped/Message/testzip.zip')
    source_folder3 = (r'J:/server/zippedMessages')
    dest_folder = ('L:/_Mine/Zipped Messages Moved')


    def check_files():
        os.listdir(source_folder3)
        zip = zipfile.ZipFile(source_file3)
        file = zip.read("bb.html")
        if b'Health in file:
            shutil.copy(source_file3, dest_folder)
            print('word found-file moved')
        else:
            print('word not found')



    folderdir = source_folder3

    for filename in os.listdir(folderdir):
        if filename.endswith(".zip"):
            source_file3 = os.path.join(folderdir, filename)
            zip = zipfile.ZipFile(source_file3)
            check_files()

Answer 1

There should be many examples how to iterate files in folder (not in ZIP file)

---

You should use for -loop with os.listdir() or glob.glob()

for filename in os.listdir(source_folder):
    if filename.endswith(".zip"):
        source_file3 = os.path.join(source_folder, filename)

        zip = zipfile.ZipFile(source_file3)

        # ... code ...

for source_file3 in glob.glob(f'{source_folder}/*.zip'):

    zip = zipfile.ZipFile(source_file3)

    # ... code ...

---

EDIT:

If you need to iterate files inside ZIP then use ZipFile.namelist() or ZipFile.infolist()

zip = zipfile.ZipFile(source_file3)

for inner_filename in zip.namelist():

    file = zip.read(inner_filename)

    # ... code ...

or

zip = zipfile.ZipFile(source_file3)

for inner_fileobject in zip.infolist():

    file = zip.read(inner_fileobject)

    # ... code ...