[英]MongoDB remove objects from nested arrays based up on the condition using aggregation
I have a nested array, I have to remove the one object, based upon the condition using aggregation我有一个嵌套数组,我必须根据使用聚合的条件删除一个 object
here is the JSON I get from mongodb这是我从 mongodb 得到的 JSON
{
"_id": "633d275ceb34a28755974032",
"name": "free",
"products": [
{
"title": "Product 1",
"phone": [
{
"title": "Best Phone 1 ",
"video": {
"Location": "https://video.mp4"
},
"freePreview": true
}
]
},
{
"title": "Product 2",
"phone": [
{
"title": "Best Phone 2",
"video": {
"Location": "https://video.mp4"
},
"freePreview": false
}
]
}
]
}
But I need the data like但我需要像这样的数据
{
"_id": "633d275ceb34a28755974032",
"name": "free",
"products": [
{
"title": "Product 1",
"phone": [
{
"title": "Best Phone 1 ",
"video": {
"Location": "https://video.mp4"
},
"freePreview": true
}
]
},
{
"title": "Product 2",
"phone": [
{
"title": "Best Phone 2",
"freePreview": false
}
]
}
]
}
In this data "video object" is removed inside the phone array, because of freePreview is false,在此数据中,由于 freePreview 为 false,phone 数组中的“视频对象”被删除,
Based upon the freePreview condition, help me to remove the video object
根据freePreview条件,帮我把视频object删掉
You need to use double $map operator to iterate through your array of arrays and use $cond along with $$REMOVE
to remove value conditionally:您需要使用双$map运算符遍历 arrays 数组,并使用$cond和
$$REMOVE
有条件地删除值:
db.collection.aggregate([
{
$addFields: {
products: {
$map: {
input: "$products",
as: "p",
in: {
title: "$$p.title",
phone: {
$map: {
input: "$$p.phone",
in: {
title: "$$this.title",
freePreview: "$$this.freePreview",
video: {
$cond: {
if: {
$eq: [
false,
"$$this.freePreview"
]
},
then: "$$REMOVE",
else: "$$this.video"
}
}
}
}
}
}
}
}
}
}
])
@mickl's answer works great. @mickl 的回答很有效。 If you want to allow for possible document/schema changes, then rather than specifying the fields to keep explicitly, you could use
"$mergeObjects"
to keep everything and then only modify what you need.如果您想允许可能的文档/架构更改,那么与其明确指定要保留的字段,不如使用
"$mergeObjects"
来保留所有内容,然后只修改您需要的内容。
Borrowing heavily from @mickl, here's how you could do that.从@mickl 大量借用,这就是你如何做到这一点。
db.collection.aggregate([
{
$addFields: {
products: {
$map: {
input: "$products",
as: "p",
in: {
"$mergeObjects": [
"$$p",
{
phone: {
$map: {
input: "$$p.phone",
in: {
"$mergeObjects": [
{
"$arrayToObject": {
"$filter": {
"input": {"$objectToArray": "$$this"},
"as": "kv",
"cond": {"$ne": ["$$kv.k", "video"]}
}
}
},
{
video: {
$cond: {
if: {
$eq: [
false,
"$$this.freePreview"
]
},
then: "$$REMOVE",
else: "$$this.video"
}
}
}
]
}
}
}
}
]
}
}
}
}
}
])
Try it on mongoplayground.net .在mongoplayground.net上试用。
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