用于检查字符串是否仅包含数字和运算符（但没有 2 个连续运算符）的正则表达式

Question

I'm trying to check if a user-entered string is a valid expression:

1. There can't be any letters [a-zA-z]
2. We're only dealing with integers
3. Spaces are allowed
4. The only valid operators are '+', '-', and '*' (no dividing)
5. There can't be two consecutive operators (so "123 ++ 456" would be invalid)
6. An operator must be followed by digits ("123 + " would be invalid but "345678 * 6" would be okay)

So far my current code userInput.matches("[0-9(+*\\-\\s)]+") can process requirements 1-4. How can I modify my regex to meet criteria 5 and 6?

Answer 1

You may use this code:

bool valid = userInput.matches("\\d+(?:\\h*[+*-]\\h*\\d+)*");

If you want to allow signed - numbers then use:

bool valid = userInput.matches("-?\\d+(?:\\h*[+*-]\\h*-?\\d+)*");

If there can be leading/trailing spaces then use:

bool valid = userInput
   .matches("\\h*-?\\d+(?:\\h*[+*-]\\h*-?\\d+)*\\h*");

Breakup:

• \\d+ : Match 1+ digits
• (?: : Start non-capture group
  • \\h* : Match 0 or more whitespaces
  • [+*-] : Match + or * or -
  • \\h* : Match 0 or more whitespaces
  • \d+`: Match 1+ digits
• )* : End non-capture group. Repeat this group 0 or more times