正则表达式包括除空格外的所有特殊字符

Question

I have a regex which checks all the special characters except space but that looks weird and too long.

const specialCharsRegex = new RegExp(/@|#|\$|!|%|&|\^|\*|-|\+|_|=|{|}|\[|\]|\(|\)|~|`|\.|\?|\<|\>|,|\/|:|;|"|'|\\/).

This looks too long and if i use regex (\W) it also includes the space.
Is there is any way i can achieve this?

Answer 1

Well you could use:

[^\w ]

This matches non word characters except for space. You may blacklist anything else you also might want by adding it to the above character class.

Answer 2

To match anything that is not a word character nor a whitespace character (cr, lf, ff, space, tab)

const specialCharsRegex = new RegExp(/[^\w\s]+|_+/, 'g');

See this demo at regex101 or a JS replace demo at tio.run (used g flag for all occurrences)

The underscore belongs to word characters [A-Za-z0-9_] and needs to be matched separately .

Answer 3

Try this using aA-0-9/az/AZ

Pattern regex = Pattern.compile("[^A-Za-z0-9]");