Python 用于从 zip 文件夹中提取文件名包含且不应包含特定模式的文件的正则表达式

Question

I want to extract just one specific single file from the zip folder which has the below 3 files.
Basically it should start with 'kpidata_nfile' and should not contain 'fileheader'

kpidata_nfile_20220919-20220925_fileheader.csv
kpidata_nfile_20220905-20220911.csv
othername_kpidata_nfile_20220905-20220911.csv

Below is my code i have tried-

from zipfile import ZipFile
import re
import os
for x in os.listdir('.'):
  if re.match('.*\.(zip)', x):
      with ZipFile(x, 'r') as zip:
          for info in zip.infolist():
              if re.match(r'^kpidata_nfile_', info.filename):
                  zip.extract(info)

Output required - kpidata_nfile_20220905-20220911.csv

Answer 1

This regex does what you require:

^kpidata_nfile(?:(?!fileheader).)*$

See this answer for more about the (?:(?.fileheader).)*$ part.

You can see the regex working on your example filenames here .

The regex is not particularly readable, so it might be better to use Python expressions instead of regex. Something like:

fname = info.filename
if fname.startswith('kpidata_nfile') and 'fileheader' not in fname: