Google Apps 脚本过滤

Question

I have some data in google sheet which I want to filter based on a certain criteria and return a corresponding value from another column. Lastly, count the number of elements in the returned column. Here is a sample data:

Sample data

	A	B
1	Initials	Application Reference
2	MWB.KBB	1001
3	JET,JJB	1002
4	KBB	100,310,041,005
5	MKGC	1006
6	KBB	1007

Let's say I want to filter the data by searching for "KBB". I want to get all cells that contain the word "KBB" which should be three (3) cells. However, I am only getting two in return. The 1st row that contain two elements in a single cell is not included but it should be included. Lastly, count the elements in the returned column based on the criteria.

Here's the code I have tried:

function filter(){
  //opened ss via url
  const ws = ss.getSheetByName("Sample");
  const range = ws.getRange(2,1,ws.getLastRow() - 1,2).getValues();

  const initial = range.map(function(n){return n[0];});
  const filtered = initial.filter(filterLogic);

  Logger.log(initial); // [MWP, KBB, JET, JJB, KBB, MKGC, KBB]
  Logger.log(filtered); // [KBB, KBB]
}

function filterLogic(name){
  if(name == "KBB"){
    return true;
  } else {
    return false;
  }
}

The above code is only for the criteria. Not included is the counting of elements for the returned value from another column after the filter is applied.

What should I do so I can include the first row that contains the text "KBB" as well in my filtered data. Is there any other way around this?

Answer 1

Code:

function searchForKBB(n = "KBB") {
  const ss = SpreadsheetApp.getActive();
  const sh = ss.getSheetByName("Sheet0");
  const osh = ss.getSheetByName("Sheet1");
  let o = sh.getRange(1,1,sh.getLastRow(),sh.getLastColumn()).createTextFinder(n).matchEntireCell(false).findAll().map(rg => [rg.getA1Notation()]);
  o.unshift(["Ranges"]);
  osh.getRange(1,1,o.length,o[0].length).setValues(o)
}

Data:

	A	B
1	Initials	Application Reference
2	MWB.KBB	1001
3	JET,JJB	1002
4	KBB	100,310,041,005
5	MKGC	1006
6	KBB	1007

Results:

Ranges
A2
A4
A6

Answer 2

Maybe you can do this:

```
function getAllKBBs(){
      var ss = SpreadsheetApp.getActiveSpreadsheet();
      var ss1 = ss.getSheetByName("YOUR_SHEET_NAME");
      var range = ss1.getRange(1,1,ss1.getLastRow(),4).getValues();
      output = whenTextContains("KBB", range, 1, 1);
      Logger.log(output.length);
} ```

where whenTextContains() function is in this repository https://github.com/NikolaPlusEqual/GoogleAppsScriptFilters/blob/main/Functions

Or, you can copy this into you code and call above function:

function letterToColumn(letter){
  var column = 0, length = letter.length;
  for (var i = 0; i < length; i++)
  {
    column += (letter.charCodeAt(i) - 64) * Math.pow(26, length - i - 1);
  }
  return column;
}
////// source for letterToColumn() function :
////// https://stackoverflow.com/questions/21229180/convert-column-index-into-corresponding-column-letter

var setData = {}

function whenTextContains(txt, rng, col, targetCol = 0){
  if (typeof col == "number" && typeof txt == "string"){
    setData.col = col;
    setData.txt = txt;
  }
  else{
    return;
  }
  var output = rng.filter(wtc);
  if(targetCol == 0){
    return output;
  }
  else if(typeof targetCol == "number"){
    var result = output.map(function (item) {
      return item[targetCol-1];
    });
    return result;
  }
  else if(typeof targetCol == "string"){
    var targetnum = letterToColumn(targetCol);
    var result = output.map(function (item) {
      return item[targetnum-1];
    });
    return result;
  }
  else{
    return;
  }
}

function wtc(ar){
  var txt = setData.txt;
  var col = setData.col - 1;
  var str =  ar[col].toString();
  return str.includes(txt);
}