在 Req.Form.Files c# 中使用 function 应用程序在 PostAsync 中使用 HttpClient 发送文件

Question

I have created Function App for uploading multiple files on FTP server. I have received all files using req.Form.Files . but When I get the request. I actually found my file from HttpClient request in req.Body . When I upload file from Postman in Body->FormData it, works fine but now I need to send post request with file by code.

I had tried below code with reference of Sending a Post using HttpClient and the Server is seeing an empty Json file this link.

HttpContent content = new StreamContent (stream);
content.Headers.ContentType = new MediaTypeHeaderValue("multipart/form-data");
HttpResponseMessage response = client.PostAsync ("url", content).Result;

But I want file in req.Form.Files . Where user might have uploaded multiple files or one file.

Note: For now I have a file which is being generated by code. But it should not be saved on local so I'm trying to send stream. in HttpContent

Answer 1

Below are the steps for Post Async using function app

 public static async Task<IActionResult> Run(
            [HttpTrigger(AuthorizationLevel.Anonymous, "post", Route = null)] HttpRequest req, ILogger log)
        {
            string Connection = Environment.GetEnvironmentVariable("AzureWebJobsStorage");
            string containerName = Environment.GetEnvironmentVariable("ContainerName");
            var file = req.Form.Files["File"];**
            var filecontent = file.OpenReadStream();
            var blobClient = new BlobContainerClient(Connection, containerName);
            var blob = blobClient.GetBlobClient(file.FileName);
            byte[] byteArray = Encoding.UTF8.GetBytes(filecontent.ToString());

File details while using req.Form.Files

Successfully uploaded a text file to blob storage.

Edit :

Here is the Post request Using HttpClient

 var file = @"C:\Users\...\Documents\test.txt";
        await using var stream = System.IO.File.OpenRead(file);
        using var request = new HttpRequestMessage(HttpMethod.Post, "file");
        using var content = new MultipartFormDataContent
         {
            { new StreamContent(stream),"File", "test.txt" }
         };
        request.Content = content;
        await client.SendAsync(request);
        return new OkObjectResult("File uploaded successfully");