更改元组列表中的元组

Question

I am reading in data from multiple Excel files and writing them back to an aggregated Excel file.

So I have this output, and it represents the relations of multiple entities within my company ( enity-ID ) with other companies ( debitor-name ):

debitor_list = [
    ("1", "X AG"),
    ("1", "X AG"),
    ("1", "Z AG"),
    ("2", "X AG"),
    ("2", "X AG"),
    ("3", "LOL AG"),
    ("1", "Z AG"), 
    ("1", "HS AG"),
    ("2", "hs ag")
]

The tuples structure within this list is the following:

('entity-ID', 'debitor-name')

In addition, I have a list which represents the real names and information about debitors:

real_file = ["LOLLIPOP AG", "HS AG", "X AG", "Z AG"]

Then I am checking for similarities between debitor name in debitor_list and real_file to replace with the real name:

import difflib as dif

for deb in debitor_list:
    for cam in cam_file:
        if deb[1] != cam:
            sequence = dif.SequenceMatcher(
                isjunk=None,
                a=deb[1].lower(),
                b=cam.lower()
            )
            match = sequence.ratio() * 100
            if (match >= 80):
                print(deb[1], cam, match)
                debitor_list.append((deb[0], cam))

Output:

hs ag HS AG 100.0

How can I delete the ("2", "hs ag") tuple?

Answer 1

Either you replace the whole list, or you replace the element in place with some simple logic, see the 2 options below.

Note that tuples might be immutable, but the list itself is not...

import difflib as dif

debitor_list = [
    ("1", "X AG"),
    ("1", "X AG"),
    ("1", "Z AG"),
    ("2", "X AG"),
    ("2", "X AG"),
    ("3", "LOL AG"),
    ("1", "Z AG"),
    ("1", "HS AG"),
    ("2", "hs ag"),
]

real_file = ["LOLLIPOP AG", "HS AG", "X AG", "Z AG"]


def fix_stuff(d_list, c_list):
    result = []
    for deb in d_list:
        repl_val = None
        for cam in c_list:
            if deb[1] != cam:
                sequence = dif.SequenceMatcher(
                    isjunk=None, a=deb[1].lower(), b=cam.lower()
                )
                match = sequence.ratio() * 100
                if match >= 80:
                    repl_val = cam
        if repl_val:
            result.append((deb[0], repl_val))
        else:
            result.append(deb)
    return result


print(debitor_list)
new_deb_list = fix_stuff(debitor_list, real_file)
print(new_deb_list)


for idx, deb in enumerate(debitor_list):
    for cam in real_file:
        if deb[1] != cam:
            sequence = dif.SequenceMatcher(isjunk=None, a=deb[1].lower(), b=cam.lower())
            match = sequence.ratio() * 100
            if match >= 80:
                debitor_list[idx] = (deb[0], cam)
print(debitor_list)

output

[('1', 'X AG'), ('1', 'X AG'), ('1', 'Z AG'), ('2', 'X AG'), ('2', 'X AG'), ('3', 'LOL AG'), ('1', 'Z AG'), ('1', 'HS AG'), ('2', 'hs ag')]
[('1', 'X AG'), ('1', 'X AG'), ('1', 'Z AG'), ('2', 'X AG'), ('2', 'X AG'), ('3', 'LOL AG'), ('1', 'Z AG'), ('1', 'HS AG'), ('2', 'HS AG')]
[('1', 'X AG'), ('1', 'X AG'), ('1', 'Z AG'), ('2', 'X AG'), ('2', 'X AG'), ('3', 'LOL AG'), ('1', 'Z AG'), ('1', 'HS AG'), ('2', 'HS AG')]

---

The if repl_val checks if the value needs to be replaced. Since the variable repl_val gets set to None at the start of each for, if repl_val will only be true if it was changed during the loop.

As for using result , when using the function, we're not modifying the incoming lists, but we return a new list result .

---

as for the second way to do this (and that is likely the better way), due to the usage of enumerate we get an index ( idx ) for each list element, as well as the value deb . It allows for directly assigning to the original list by it's index, so it's a direct modification of the original list.