（已解决）Python：While 循环未按预期运行

Question

I am new to python and am trying to make a calculator. I have +, -, *, / and raising to the power of x done and am trying to do have a function that finds the square root of a number. I had a version working but it only worked if there was a number that was exactly the square root. As in 3 is exactly the square root of 9 but if the square root had a decimal such as the square root of 6.5 it would crash. I wanted it to be able to do the float numbers as well. The way I was doing it originally was:

tempAns = 1
while tempAns <= num1:
    if tempAns * tempAns == num1:
        answer = tempAns
        break

    tempAns += 1

print('The answer is: ' + str(answer))

But my problem was that as I was incrementing it by 1 it was missing the numbers in between. I tried to increment it by 0.1 each time with:

tempAns = 0.1
while tempAns <= num1:
    if tempAns * tempAns == num1:
        answer = tempAns
        break

    tempAns += 0.1

print('The answer is: ' + str(answer))

But this just gave me an error saying: UnboundLocalError: local variable 'answer' referenced before assignment

I have absolutely no idea why this is happening as it should be looping until it assigns a number to 'answer' .

Any help will be appreciated. Also any suggestions on how to make my code cleaner would be nice as I'm new to python. Thanks in advance!

Answer 1

sqrt() function is an inbuilt function in Python programming language that returns the square root of any number .

Syntax: math.sqrt(x)

Parameter: x is any number such that x>=0

Returns: It returns the square root of the number passed in the parameter.