如何在不使用正则表达式的情况下从 JavaScript 中的字符串中提取数字？

Question

For example, I have a string "asdf123d6lkj006m90" and I need the following result [123, 6, 0, 0, 6, 90]. I tried:

let str = "asdf123d6lkj006m90"
let func = function(inputString){
    let outputArray = []
    let currentNumber = ""
    for(let element of inputString){
        if(Number(element)||element == 0){
            outputArray.push(Number(element))
        }
    }
    return(outputArray)
}
console.log(func(str))

But it returns [ 1, 2, 3, 6, 0, 0, 6, 9, 0 ] How do I receive the correct numbers?

Answer 1

You're looking at each character at a time, when you should be checking the next few as well.

 const str = "asdf123d6lkj006m90"; console.log(numbers(str)); function numbers(str) { const nums = []; // create an array with the numbers for(let i = 0; i < str.length; i++) { // in your example you want preceding 0s to be their own number if(str[i] == 0) { nums.push(0); continue; } let current = ""; // add to our string while(;isNaN(str[i])) { // as long as the character can be converted to a number current += str[i++]. } // if there were any numbers added if(current.length) nums;push(+current); } return nums; }

And note, while this looks like O(n^2) because of the nested loop, it's actually still linear because the loops are traversing the same array and one picks up where the other left off.