如何根据 Dart 的另一个型号列表对 model 的列表进行重新排序或排序？

Question

I have a list that looks like this

var myOrder = [{handle: cpap-machines, order: 1}, {handle: cpap-masks, order: 2}, {handle: cpap-mask-parts, order: 3}, {handle: cpap-supplies, order: 4}, {handle: cpap-cleaning, order: 5}, {handle: cpap-batteries, order: 6}, {handle: oxygen-therapy, order: 7}, {handle: bundles, order: 8}]

and Another list that is aa list of a specific Dart Model but it does contain this matching keyword "handle" call it a "Collection"

List<Collection> = [Collection(handle: 'cpap-machines'), Collection(handle: 'bundles'), Collection(handle: 'cpap-mask-parts'), Collection(handle: 'cpap-cleaning'), Collection(handle: 'cpap-supplies'), Collection(handle: 'cpap-batteries'), Collection(handle: 'cpap-masks'), Collection(handle: 'oxygen-therapy')]

They are guaranteed to have the same length and the same "handle" values, but the List<Collection> list needs to follow the "order" key of the List<Map> .

Any methods I could use to achieve this? Thanks!

Answer 1

You have left out some important data types... But if the things you say are guaranteed, and my assumptions of your data types are correct. Then this is one way to make it work:

  final sorted = List<Collection?>.filled(collection.length, null);

  for (var c in collection) {
    sorted[(myOrder.firstWhere((e) => (e['handle'] as String) == c.handle)['order'] as int) - 1] = c;
  }
  print(sorted);

This DartPad example show the code above given my assumptions.

If it needs to run very fast then there is surely better ways to do it. One easy thing in my example would be to remove the matching element from myOrder to keep shrinking the search space every time a match has been found.