在数组中查找以特定字符开头的单词的字符串

Question

If I have array of string like

const arrayOfString=["Ajay Choudhary","Charlli Chouhan","Kerri Cilce","Dalis Menary"];

How to get name which has startswith C and surname startswith C like my output will be

Ajay Choudhary
Charlli Chouhan
Kerri Cilce

I have tried below but it does not give expected output

 const arrayOfString = ["Ajay Choudhary", "Charlli Chouhan", "Kerri Cilce", "Dalis Menary"]; arrayOfString.forEach(element => { //console.log(element); if (element.startsWith("C")) { //console.log(element); } if (element.charAt(element.charAt(-1)).startsWith("C")) { console.log(element); } });

Answer 1

You can use simple regex to check if any of words starts with C :

 const arrayOfString=["Ajay Choudhary","Charlli Chouhan","Kerri Cilce","Dalis Menary", "Karoline-Celvin Boobier"]; arrayOfString.forEach(element => { if (/\bC\w+/.test(element)) { console.log(element); } });

Answer 2

Filter on the letter. I assume all names will start with capital letter

Note: McCain will be included too.

 const arrayOfString = ["Ajay Choudhary", "Charlli Chouhan", "Kerri Cilce", "Dalis Menary"]; const cNames = arrayOfString.filter(name => name.includes("C")) console.log(cNames)

If you want to avoid names like McCain, then you can split and filter on startsWith

 const arrayOfString = ["Ajay Choudhary", "Charlli Chouhan", "Kerri Cilce", "Dalis Menary", "Noddy McCain"]; const cNames = arrayOfString.filter(name => name.split(" ").some(name => name.startsWith("C"))); // either first or lastname(s) starts with letter C console.log(cNames)

Answer 3

I think, spliting words with space and then filtering base on starting with 'C' will do what you want.

here is what I did:

arrayOfString.filter(name=>name.split(' ').filter(n => n.startsWith('C')).length > 0)

 const arrayOfString = ["Ajay Choudhary", "Charlli Chouhan", "Kerri Cilce", "Dalis Menary"]; const result = arrayOfString.filter(name=>name.split(' ').filter(n => n.startsWith('C')).length > 0) console.log(result)